I admit, I like non-alcohol beers occasionally. I like the taste, and I like not falling asleep shortly thereafter while watching TV. However, I noticed something rather unusual recently on an O'Doul's label. Not only unusual but contradictory. I think. O'Doul's label says "non-alcoholic." (see photo above)
It also says, in smaller type, "contains less than 0.5% alcohol by volume." (see second photo above) Now that says to me it contains alcohol, it's just less than .5%. Does that mean if I drink 10 O'Doul's (or any of the other "non-alcohol" brews), I'll have drunk the equivalent of a "real" beer? There is probably a legal description or escape clause somewhere that helps legitimize this. Granted, I don't fall asleep after having one or two. Another non-alcohol beer is high on my list of favorite brews: Buckler. It's made by Heineken. Talk about full, rich beer taste. I think it's what Joe Biden drank in that strange presidential beer blast last year. Buckler, too, "contains less than 0.5 etc". Not a big deal, really. Just wondering if anyone has any insight into that category.